100x^2+500x-600=0

Solution for 100x^2+500x-600=0 equation:

100x^2+500x-600=0

a = 100; b = 500; c = -600;
Δ = b2-4ac
Δ = 5002-4·100·(-600)
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{490000}=700$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-700}{2*100}=\frac{-1200}{200}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+700}{2*100}=\frac{200}{200}
=1
$